Question 1090238

in {{{a + bi}}} form:

7.  {{{2/(3i)}}}=> {{{0 + (2*3i)(3i)^2=0 + (2*3i)(9*-1) = 0-(2i)/3= 0-(2/3)i}}}

8.  {{{4/2i}}}=> {{{0 + 4/(2i)=0 + (4*2i)/(2i)^2=0 + (4*2i)/(4*-1)=0-2i}}}

12.  {{{5i/4 - i}}}=>{{{0+5i/4 - 4i/4=0+i/4=0+(1/4)i}}}