Question 1090210
2x^3-4x^2+2x = 2x(x^2-2x+1) = 2x(x-1)^2

So the roots are: 2x(x-1)^2 =0

                  2x=0 or (x-1)^2 = 0

                   x=0 or x=1 (with multiplicity =2)

Roots={0,1,1}

@natolino_