Question 96679
2x^2+10x+11=0   a=2 b=10 c=11 
use quadratic formula and substitue value of a,b and c 
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
then you will get 2 x values which will be negative 1.63397 and negative3.3660
but always round ur answer off to 3 significant figures