Question 1090161
{{{y-x=32}}}
{{{y=x+32}}}
So then,
{{{xy=x(x+32)}}}
{{{xy=x^2+32x}}}
Complete the square,
{{{xy=(x^2+32x+256)-256}}}
{{{xy=(x+16)^2-256}}}
So the minimum occurs when {{{x=-16}}} and is equal to {{{-256}}} so {{{y=16}}}