Question 1090057
one is 5000(1+.025)^4n
other is 10000(1+.0125)^4n
this is equivalent to (1.025)^n and 2(1.0125)^n
The first should catch the second at some point.
set them equal.

10000(1.0125)^n=5000(1.025)^n
2(1.0125)^n=1.025^n
2=(1.025/1.0125)^n
ln both sides
ln2= n ln (1.025/1.0125)=n*0.012227
0.693=0.012227 n
n=56.49 quarterly compoundings or just over 14 years or 168 months
{{{graph(300,300,50,60,-10,10,1.025^x,2*(1.0125)^x)}}}
{{{graph(300,300,-10,70,-10,10,1.025^x,2*(1.0125)^x)}}}