Question 1088195
Part a) is after 1 month.  So P is 14000, r is 0.034, n = 12, and t = 1/12 (one month is 1/12 of a year and t is measured in years).
{{{A = 14000(1 + 0.034/12)^(12(1/12))}}}
{{{A = 14000(1.0028333) = 14039.67}}}
Part b) changes t = 1.5
{{{A = 14000(1 + 0.34/12)^(12(1.5)) = 14731.46}}}
And part c changes t = 34
{{{A = 14000(1 + 0.34/12)^(12(34)) = 44408.14}}}