Question 1090020
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He has 14 coins {{{highlight(cross(which))}}} what {{{highlight(cross(is))}}} are {{{highlight(cross(eithee))}}} either 10 dollars or 2 dollars, total {{{highlight(cross(ampunt))}}} amount is not greater than 95, how many 10 coins he has?
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<pre>
Let x = # of 10-dollar coins.
Then the number of 2-dollar coins is (14-x).


The value expression is value = 10x + 2*(14-x) dollars.


Your inequality is

10x + 2*(14-x) <= 95  ====>


Simplify and solve it step by step:


10x + 28 - 2x <= 95,

8x <= 95 - 28 = 67.  ====>  x <= 8


<U>Answer</U>.  Less than 9.
</pre>

Solved.



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Regarding the answer by @MathTherapy, I want to underline one more time: 


<pre>
    The correct answer is "the number of 10-dollar coins is less than 9", 

    which means N <= 8,   BUT NOT NECESSARY N=8.
</pre>