Question 1089976
Stacey observed that it took w women 10 days to do j jobs. Then, she calculated how long it would take n more women to do 28 more jobs. What was her answer?
<pre>{{{w = k(j)/T}}}
{{{w = k(j)/10}}}
kj = 10w ------- Cross-multiplying
{{{matrix(1,3, k, "=", 10w/j)}}}

{{{matrix(1,3, w, "=", k(j)/T)}}}
{{{matrix(1,3, w + n, "=", ((10w/j) * (j + 28))/T))}}} ------ Adding n MORE women, and 28 MORE jobs
{{{matrix(1,3, T(w + n), "=", 10w(j + 28)/j)}}} ---------- Cross-multiplying
{{{matrix(1,3, T, "=", ((10jw + 280w)/j)/(w  + n))}}}
T, or time = {{{highlight_green(matrix(1,6, ((10jw + 280w)/j) * (1/(w + n)), "=", (10jw + 280w)/j(w + n), ",", "or", (10jw + 280w)/(jw + jn)))}}}