Question 1089981
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<pre>
What I see in the first line, this phrase

    "how many unique arrangments (different people on left and right) how many arrangments are possible when seating 6?"


is not a formulation of a math problem.  It is rather somebody's fantasy.


The correct formulation is THIS:

    how many different arrangements are possible for 6 people seating in row ?


And then the answer is:  6! = 1*2*3*4*5*6 = 720.


Any of           6 in the most left position;
Any of remaining 5 in the next position;
Any of remaining 4 in the next position;
Any of remaining 3 in the next position;
Any of remaining 2 in the next position;
And for the last position there is only one possibility.


In all, there are 720 arrangements.
</pre>

Solved.


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Next time, when you need HELP in solving your assignment, write it word-in-word as it is formulated in  your assignment, PLEASE.
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On Permutations, &nbsp;see the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =http://www.algebra.com/algebra/homework/Permutations/Introduction-to-Permutations.lesson>Introduction to Permutations</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =http://www.algebra.com/algebra/homework/Permutations/PROOF-of-the-formula-on-the-number-of-permutations.lesson>PROOF of the formula on the number of Permutations</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =http://www.algebra.com/algebra/homework/Permutations/Problems-on-Permutations.lesson>Problems on Permutations</A>

in this site.


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-II in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-II - YOUR ONLINE TEXTBOOK</A>.


The referred lessons are the part of this online textbook under the topic &nbsp;"<U>Combinatorics: Combinations and permutations</U>".