Question 1089725
So there are 
{{{23+10+1=34}}} total values.
and the probability for each value is {{{P=1/34}}}
So then,
{{{E=sum((X*P(X)),X=-10,23)}}}
{{{E=(1/34)*sum((X),X=-10,23)}}}
{{{E=(1/34)(221)}}}
{{{E=221/34}}}
{{{E=13/2}}}
Your expected winning would be {{{13/2}}} or $6.50.