Question 96623
:

{{{((6p-18))/(9p)}}} 
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{{{((3p-9))/((p^2+2p))}}}
:
Invert the dividing fraction and multiply:
{{{((6p-18))/(9p)}}} * {{{((p^2+2p))/((3p-9))}}}
:
Factor:
{{{(6(p-3))/(9p)}}} * {{{(p(p+2))/(3(p-3))}}}
:
Cancel (3-p), p, 
{{{(6)/(9)}}} * {{{((p+2))/(3)}}} 
:
Cancel 3 into 6
{{{(2)/(9)}}} * (p+2) = {{{(2(p+2))/9}}}
:
Could you follow this OK?