Question 1089923

if the circle given by the equation {{{x^2 +y^2 +6x+2y+6=0}}}, first write it in {{{(x-h)^2+(y-k)^2=r^2}}} form and find a radius

{{{(x^2+6x) +(y^2 +2y)+6=0}}}...complete square

{{{(x^2+6x+b^2)-b^2 +(y^2 +2y+b^2)-b^2+6=0}}}

{{{(x^2+6x+3^2)-3^2 +(y^2 +2y+1^2)-2^2+6=0}}}

{{{(x+3)^2-9 +(y+1)^2-1+6=0}}}

{{{(x+3)^2 +(y+3)^2-10+6=0}}}

{{{(x+3)^2 +(y+3)^2-4=0}}}

{{{(x+3)^2 +(y+3)^2=4}}}


{{{(x+3)^2 +(y+3)^2=2^2}}}=> {{{r=2}}}

the area is {{{A=r^2pi}}}=>{{{A=2^2pi}}}=>=>{{{A=4pi}}} approximately {{{A=12.56}}}