Question 96799
x, x+2, x+4 are the three integers
4(x+x+4)=4 times the sum of the 1st and 3rd.
6(x+2)=6 times the middle.
Don't forget to add 20 to the left side to make it equal to the right!
4(2x+4)+20=6(x+2)
8x+16+20=6x+12
subtract 6x and 36 from both sides.
2x=-24
divide 2 into both sides. x=-12 x+2=-10 x+4=-8
Check:
4(-12+(-8))=4*-20=-80
6*-10=-60
-80 is 20 less than -60
Ed