Question 1089671

This problem was labled in my textbook as a nonlinear equation, but I couldn't find a better spot to put it. 

 X^2+y^2=3
{
 x-y=2

I'm ending up with x= plus or minus sqrt14/2 my textbook has x as plus or minus 1. 
Could you explain to me where I'm going wrong?

Thank you!

p.s. I wasn't quite sure how to notate the fact that the two equations went together so I just did the little brackets between them. I'm not a math person, so if you could be very clear and explicit that would be much appreciated. Thanks again!
<pre>I DETEST these types of problems that DON'T have INTEGER solutions.

{{{matrix(1,6, x^2 + y^2, "=", 3, "----------", eq, "(i)")}}}
x - y =  2______x = 2 + y ------- eq (ii)
{{{(2 + y)^2 + y^2 = 3}}} ------- Substituting 2 + y for x in eq (i)
{{{4 + 4y + y^2 + y^2 = 3}}}
{{{2y^2 + 4y + 4 - 3 = 0}}}
{{{2y^2 + 4y + 1 = 0}}}
Using the quadratic equation formula, or Completing the Square, solve for y.
You should get 2 different values for y, which are: {{{highlight_green(matrix(1,3, "- 0.292893219,", and, - 1.7071))}}}
Substitute each value for y into any of the 2 ORIGINAL equations (2nd equation is EASIER) to get the 2 corresponding values for x. 
There you have it! All done!!