Question 1089530
The equation for this ball's movement would be h(t)=-16t²+120t+200, where t is time and h(t) is the ball's height at any given t. The ball will reach its maximum height at t=-b/2a, where b is the initial velocity(120), and a is the acceleration (-16a). In this case, -b/2a=-120/-32=3.75 seconds before the ball reaches its maximum height. Then:
-16(3.75²)+120(3.75)+200=425 ft is the ball's maximum height. 
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