Question 1089494
Let n = the first number
Let m = the 2nd number

{{{ n = m - 10 }}}  —>  {{{ m-n = 10 }}}   (1)
{{{ 2m = 59+5n }}} —>  {{{ 2m-5n = 59 }}}  (2)

2*(1) —>   {{{ 2m - 2n = 20 }}}
subtract (2) {{{ 2m-5n = 59 }}}
resulting in:   {{{  3n = -39 }}}

Ans:   {{{ highlight(n = -13)}}}   and  {{{ highlight(m = -3 )}}}
——
Check:  -13 is 10 less than -3  (ok)
              2(-3) = -6
              59 + 5(-13) = 59+(-65) = -6   (ok)