Question 1089400
{{{(G[1]+G[2]+G[3])/3=4}}}
So then,
{{{G[1]+G[2]+G[3]=12}}}
Adding D,
{{{(G[1]+G[2]+G[3]+G[4])/4=5}}}
{{{G[1]+G[2]+G[3]+G[4]=20}}}
Substituting,
{{{12+G[4]=20}}}
Solve for {{{G[4]}}}.