<PRE><B>Question 96642</B>
 14x- 7 * x²+6x+8 ÷ x²+24
_______ ________ ______
x²+3-4 2x²+5x-3 x² + 2x-3
:
Invert the dividing fraction and mulitply
{{{((14x-7))/((x^2+3x-4))}}} * {{{((x^2+6x+8))/((2x^2+5x-3))}}} *  {{{((x^2+2x-3))/((x^2+24))}}}
:
Factor:
{{{(7(2x-1))/((x+4)(x-1))}}} * {{{((x+2)(x+4))/((2x-1)(x+3))}}} *  {{{((x-1)(x+3))/((x^2+24))}}}
:
Cancel (2x-1), (x+4), (x+3) and (x-1)
:
7 * (x+2) * {{{1/((x^2+24))}}} = {{{(7(x+2))/((x^2+24))}}}</PRE>