Question 1089295
{{{3}}} shirts and {{{5}}} ties costs ${{{60}}} 
and {{{2}}} shirts and {{{3}}} ties costs ${{{39}}}
{{{x = shirts}}}
{{{ y = ties}}}

{{{3x + 5y = 60}}}....eq.1
{{{2x + 3y = 39}}} ....eq.2

solve this system:

start with {{{3x + 5y = 60}}}....eq.1 and solve for {{{x}}}

{{{3x + 5y = 60}}}
{{{3x = 60-5y}}}
{{{x = 60/3-5y/3}}}
{{{x = 20-5y/3}}}-> substitute it in eq.2

{{{2(20-5y/3)+ 3y = 39}}} ....eq.2

{{{40-10y/3+ 3y = 39}}}

{{{3*40-(10y)3/3+ 3*3y = 3*39}}}

{{{120-10y+ 9y = 117}}}

{{{120-y = 117}}}

{{{120-117 = y}}}

{{{y=3}}}

now find {{{x}}}

{{{x = 20-(5*3)/3}}}

{{{x = 20-5}}}

{{{x = 15}}}


shirt cost ${{{15}}}
tie cost $ {{{ 3}}}