Question 1089284
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... a y intercept of 6 and cuts the x axis at 2 and 3 .
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{{{y=a(x-2)(x-3)}}}
{{{a=y/((x-2)(x-3))}}}
{{{a=6/((0-2)(0-3))}}}
{{{a=6/6}}}
{{{a=1}}}


{{{y=1(x-2)(x-3)}}}


{{{highlight(y=(x-2)(x-3))}}}
OR
{{{highlight(y=x^2-5x+6)}}}