Question 1089246


find: the value of "{{{a}}}" 

if a line: {{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept
 
given: 
has a y-intercept of {{{6}}} and 
slope of {{{-2/3}}}

 {{{y=-(2/3)x+6}}}

containing the point ({{{a}}}, {{{-2a}}}) =({{{x}}}, {{{y}}})

{{{-2a=-(2/3)a+6}}} ........solve for {{{a}}}

{{{-2a*3=-3(2/3)a+6*3}}}

{{{-6a=-2a+18}}}

{{{-18=-2a+6a}}}

{{{-18=4a}}}

{{{-18/4=a}}}

{{{a=-9/2}}}

and point is:({{{-9/2}}}, {{{-2(-9/2)}}})->({{{-9/2}}}, {{{9}}})

{{{drawing( 600, 600, -10, 10, -10, 10, 
circle(-9/2,9,.12), locate(-9/2,9,p(-9/2,9)),
 graph( 600, 600, -10, 10, -10, 10, -(2/3)x+6)) }}}