Question 1089221
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Row 1: 


If x = 0, then 


{{{y = 3x+2}}}


{{{y = 3(0)+2}}} Replace x with 0


{{{y = 0+2}}}


{{{y = 2}}}


So the value x = 0 pairs up with y = 2.


The fact that x is 0 here indicates we have an y intercept. This is where the graph crosses the y axis.


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Row 2: 


If x = 2, then


{{{y = 3x+2}}}


{{{y = 3(2)+2}}} Replace x with 2


{{{y = 6+2}}}


{{{y = 8}}}


So the value x = 2 pairs up with y = 8.


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Row 3:


If y = 0, then


{{{y = 3x+2}}}


{{{0 = 3x+2}}} Replace y with 0


{{{0-2 = 3x+2-2}}} Subtract 2 from both sides


{{{-2 = 3x}}}


{{{3x = -2}}}


{{{3x/3 = -2/3}}} Divide both sides by 3


{{{x = -2/3}}} 


So the value x = -2/3 pairs up with y = 0.


The fact that y is 0 here indicates we have an x intercept. This is where the graph crosses the x axis.


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Row 4:


If y = 5, then


{{{y = 3x+2}}}


{{{5 = 3x+2}}} Replace y with 5


{{{5-2 = 3x+2-2}}} Subtract 2 from both sides


{{{3 = 3x}}}


{{{3x = 3}}}


{{{3x/3 = 3/3}}} Divide both sides by 3


{{{x = 1}}}


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Here's a look at the full completed table (updated entries in <font color=red>red</font>)


<table border=1><tr><th>x</th><th>y</th></tr><tr><td style="width:150px">0</td><td style="width:150px"><font color=red>2</font></td></tr><tr><td>2</td><td><font color=red>8</font></td></tr><tr><td><font color=red>-2/3</font> (see <font color=blue>note</font> below)</td><td>0</td></tr><tr><td><font color=red>1</font></td><td>5</td></tr></table>


<font color=blue>note</font>: The value x = -2/3 is approximately equal to x = -0.667 rounded to 3 decimal places


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If we plot all of the points and draw a single straight line through them, then we end up with what is shown below.


<img src = "https://image.prntscr.com/image/ozDcQy4WTCaVQOsCLcHCNw.png">


The four points are


A = (0, 2)
B = (2, 8)
C = (-2/3, 0)
D = (1, 5)


where A,B,C,D corresponds to the (x,y) pairings found in row1,row2,row3,row4 in that order. 

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