Question 1089179
If x>0 and x^y (x^1/2)=x^3/8. What is the value of "y"?
x^(y+(1/2)) = x^(3/8)
y+(1/2) = 3/8
y = -1/8
Cheers,
Stan H.
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A)1/2
B)1/3
C)1/4
D)-1/8