Question 1089138
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if a body is dropped, the distance (s meters) through which it falls freely in t seconds is approximately 16t^2.
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Before answering your questions, let me make this notice.


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    The form of the equation for freely falling body  "distance = 16*t^2" assumes that the distance is in feet, not in meters.

    It is your MISTAKE in the condition to relate the distance to meters.
    It must be in feet.
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<pre>
a.  Show that the distances through which it falls during the first, second, third,..... forms an AP?

    - See the lesson  <A HREF=http://www.algebra.com/algebra/homework/Sequences-and-series/Free-fall-and-arithmetic-progressions.lesson>Free fall and arithmetic progressions</A>  in this site. It is explained there in all details.


b.  How far will the body fall in the tenth second?    <U>Answer</U>. {{{16*10^2 - 16*9^2}}},  or, which is the same, {{{16*(10^2-9^2)}}} ft.

                                                              Please complete these calculations on your own.



c. How far will it fall the 20 seconds?                <U>Answer</U>. In {{{16*20^2}}} feet.
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