<PRE><B>Question 96669</B>
a DVD spins as fas as 1400 rpm. If the DVD is 4.87 inches in diameter how fast does the outer edge travel at maximal speed expressed in miles per hour?
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A point on the edge of the DVD will travel
1400*pi*4.87(in/min)(60min/1hr)(1 mi/12*5280 in)
= (1285162.723/63360)(mph)
= 20.28350257 mph
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 furlongs and per fortnight. 8 furlongs =1mile 14 days =1 fornight.

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20.28350257 (mi/hr)(8 fur/1 mi)(24 hr/1 day)(14 days/1 fortnight)
= (20.28350257*8*24*14)(furlongs/fortnight)
= 54522.05492(furlongs/fortnight)
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Cheers,
Stan H. 
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