Question 1089031
{{{f(n)=n^5-n}}}
{{{f(n)=n(n^4-1)}}}
{{{f(n)=n(n^2-1)(n^2+1)}}}
{{{f(n)=n(n+1)(n-1)(n^2+1)}}}
So when {{{n=N}}},
{{{f(N)=N(N+1)(N-1)(N^2+1)}}}
Then {{{f(N)}}} is divisible by,
{{{N}}},{{{N+1}}},{{{N-1}}}, and {{{N^2+1}}}.