Question 1089003
x+y+z=11
2x+4y+5z=30
6x-y=47
therefore, y=6x-47
substitute into the equations
x+6x-47+z=11 or 7x-47+z=11
2x+4(6x-47)+5z=30 or 26x-188+5z=30
7x+z=58, z=-7x+58
substitute that into the equation 26x+5z=218 so that 26x-35x+290=218
-9x=-72
x=8
26x+5z=218 so that 208+5z=218 and z=2
Going back to the first equation, 8+y+2=11 and y=1
2(8)+4(1)+5(2)=30
{8, 1, 2}