Question 14008
First, what constitutes a difference of less-than-two from a pair of dice?

Well...0 < 2 and 1 < 2

How many ways can you get a difference of zero?

6-6 = 0
5-5 = 0
4-4 = 0
3-3 = 0
2-2 = 0
1-1 = 0

Six ways.

Now, how many ways can you get a differenc of one?

6-5 = 1
5-4 = 1
4-3 = 1
3-2 = 1
2-1 = 1

Five ways.

So you can get a difference of less than two in eleven ways.

What are total possible number of different outcomes from rolling a pair of dice?

Thirtysix.

So, the probability of rolling a difference of less than two (0 or 1) is just:
p(<2) = {{{11/36}}}