Question 1088883
{{{ ( 2+i )/(1 - i) * (1+i) / (1+i) }}} 
= {{{  (2+2i+i+i^2) / (1+i-i-i^2 ) }}}
= {{{  (1 + 3i)/2 }}}
= {{{  (1/2) + (3/2)i }}}
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Comparing this to  a - bi,   we notice   {{{ highlight(a = 1/2) }}}  and  {{{ highlight(b = -3/2) }}}