Question 1088889
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There are 26 ways the first letter can be.

For each of those 26 ways, there are 26 ways the second letter can be.
That's 26×26 ways the first and second letters can be.

For each of those 26×26 ways, there are 26 ways the third letter can be.
That's 26×26×26 ways the first, second and third letters can be.

For each of those 26×26×26 ways, there are 26 ways the last letter can be.
That's 26×26×26×26 ways the first, second, third and last letters can be.

So we multiply 26×26×26×26 and get 456,976.

So there's just 1 way to get EAFC out of all those 456,976.

So the probability is 1 out of 456,876 or 1/456,976

Edwin</pre></b></font>