Question 1088858
A root of {{{x^3-ax-6}}} is {{{-2}}}.

<pre>
-2    |   1   0   -a     -6
      |
      |      -2   4    -8+2a
      |_____________________________
          1   -2   4-a   2a-14
</pre>
The remainder must be zero, 0.
{{{cross(a-14=0)}}}
{{{2a-14=0}}}
{{{a-7=0}}}
{{{highlight_green(a=7)}}}.


Now you want the synthetic division of {{{2x^3+7x^2-6x+9}}} divided by {{{x+1}}}.