Question 1088902


{{{( a-bi )= (2+i) / (1-i)}}}

{{{( a-bi )= ((2+i) (1+i)) /( (1-i) (1+i))}}}

{{{( a-bi )= (2+2i+i+i^2) / (1^2-i^2)}}}
 
{{{( a-bi )= (2+3i+(-1)) / (1-(-1)) }}}

{{{( a-bi )= (2+3i-1) / (1+1)}}}
 
{{{( a-bi )= (1+3i) / 2}}}

{{{2( a-bi )= (1+3i)}}}
 
{{{highlight(2a)-highlight(green(2bi)) = highlight(1)+highlight(green(3i)) }}}

{{{2a=1}}}=> {{{highlight(a=1/2)}}}

{{{-2bi=3i}}}...cancel {{{i}}}

{{{-2b=3}}}

{{{highlight(green(b=-3/2))}}}


and, your answer is:
D){{{highlight(a=1/2)}}}, {{{highlight(green(b=-3/2))}}}