Question 1088886
The slope of the line would be,
{{{m=(5-2)/(b-a)}}}
Solve for a and b.
{{{a^2+1=2}}}
{{{a^2=1}}}
{{{a=1}}} or {{{a=-1}}}
.
.
.
{{{b^2+1=5}}}
{{{b^2=4}}}
{{{b=-2}}} and {{{b=2}}}
.
.
.
For the greatest value of slope, make {{{a-b}}} a minimum but still positive.
So,
{{{a=1}}}
and
{{{b=2}}}
So,
{{{m=3/1=3}}}