Question 1088762
{{{g(x)=2x+1}}}
 If {{{(1/3)(g(x^2))=1}}}, we have

{{{(1/3)(2x^2+1)=1}}}....both sides multiply by {{{3}}}
 {{{2x^2+1=3}}}
 {{{2x^2+1-3=0}}}
 {{{2x^2-2=0}}}
 {{{2(x^2-1)=0}}}
 {{{2(x-1)(x+1)=0}}}
solutions:
{{{x=1}}} or{{{ x=-1}}}

and, your answer is B. {{{1}}}