Question 1088827
Exponential Decay,
just the beginning,
{{{y=p*e^(-kx)}}}
-
{{{1/2=1*e^(-6k)}}}


{{{ln(1/2)=-6k}}}

{{{-6k=-ln(2)}}}

{{{k=ln(2)/6}}}

{{{k=0.1155}}}


MODEL, {{{y=p*e^(-0.1155x)}}};


If x is time since initial release, IN DAYS, and p=1, and y=0.14, then solve for x.