Question 1088834
You can keep the time quantity as months.
2 years is 24 months.


{{{p=40000*b^23=80000}}}, because you know 23 months makes population double.

{{{b^23=2}}}

{{{log((b^23))=log((2))}}}

{{{23*log((b))=log((2))}}}

{{{log((b))=(1/23)log((2))}}}

{{{log((b))=0.013088}}}

{{{b=10^0.013088}}}

{{{b=1.0306}}}

Your 2-year population is  {{{p=40000*(1.0306)^24}}}.