Question 1088751
let f(x) = ln(x) and g(x) = ln(x+1)

f'(x) = 1/x and g'(x) = 1/(x+1)

using the quotient's formula:

(f(x)/(g(x))' = (f'(x)*g(x) - f(x)*g'(x))/(g(x))^2

              = (ln(x+1)/x -ln(x)/(x+1))/(ln^2(x+1))

              = ((x+1)(ln(x+1))-(xln(x))/((x)(x+1)(ln^2(x+1))

@natolino_