Question 1088743
{{{cos^2(theta)+cos(theta)=0}}}
{{{cos(theta)(cos(theta)+1)=0}}}
So then,
{{{cos(theta)=0}}}
{{{theta=pi/2}}} and {{{theta=(3/2)pi}}}
and
{{{cos(theta)+1=0}}}
{{{cos(theta)=-1}}}
{{{theta=pi}}}
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*[illustration dfv11.JPG].