Question 1088721
{{{A=B/2-3}}}
{{{2A=B-6}}}
and
{{{AB=540}}}
{{{2AB=1080}}}
Substituting,
{{{(B-6)B=1080}}}
{{{B^2-6B-1080=0}}}
{{{(B-36)(B+30)=0}}}
Two solutions:
{{{B-36=0}}}
{{{B=36}}}
and
{{{B+30=0}}}
{{{B=-30}}}
Now use either equation above to solve for both corresponding A values.