Question 1088735
{{{A=3B}}}
Ten years ago,
{{{A-10=5(B-10)}}}
{{{A-10=5B-50}}}
{{{A=5B-40}}}
Substituting,
{{{3B=5B-40}}}
{{{-2B=-40}}}
Solve for B, then use either equation to solve for A.