Question 1088725
{{{p=I*e^(-kt)}}}
{{{1/2=1*e^(-k*1690)}}}

{{{ln(1/2)=0-k*1690}}}
{{{-1690k=ln(1/2)}}}
{{{-1690k=-ln(2)}}}
{{{k=ln(2)/1690}}}
{{{k=0.0004101}}}


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I=40 grams
t=440 years

{{{highlight_green(40*e^(-0.0004101*440))}}}

33 grams