Question 1088662
Let {{{ s }}} = the speed going upriver in mi/hr
{{{ s + 5 }}} = the speed going downriver in mi/hr
------------------
(1) {{{ d = s*2.3 }}}
and
(2) {{{ d = ( s + 5 )*1.8 }}}
--------------------------
(2) {{{ d = 1.8s + 9 }}}
Plug (1) into (2)
(2) {{{ 2.3s = 1.8s + 9 }}}
(2) {{{ .5s = 9 }}}
(2) {{{ s = 18 }}}
------------------
The speed upriver is 18 mi/hr
-----------------
To make a table, you have:
[ upriver speed, s ], [ downriver speed, s+5 ], 
[ upriver time ], [ downriver time ]
[ upriver distance, d ] = [ downriver distance, d ]