Question 1088591
Let {{{x}}} be the amount of money invested at 12%
Let {{{y}}} be the amount of money invested at 8%
Since John invests $6000, then {{{x+y=6000}}}
He earned a total of $660 in interest, hence {{{0.12x+0.08y=660}}}
The system of equations is
{{{system(x+y=6000, 0.12x+0.08y=660)}}}
{{{system(y=6000-x, 0.12x+0.08(6000-x)=660)}}}
{{{system(y=6000-x, 0.12x+480-0.08x=660)}}}
{{{system(y=6000-x, 0.04x=180)}}}
{{{system(y=6000-x, x=180/0.04)}}}
{{{system(y=6000-4500, x=4500)}}}
{{{system(y=1500, x=4500)}}}
John invested $4500 at 12% and $1500 at 8%
Answer: $4500 at 12% and $1500 at 8%