Question 1088222
{{{t}}}= time Dominique waited at Cleveland (in hours)
{{{2t}}}= time in the air on her trip to Cleveland (in hours)
{{{150*(2t)=300t}}}= distance flown on her trip to Cleveland (in km)
{{{300t+60}}}= distance flown on the return trip (in km)
{{{(300t+60)/180=(5/3)t+1/3}}}= time in the air on the return trip (in hours)
Adding times,
{{{2t+t+(5/3)t+1/3=5}}}
Multiplying both sides of the equation times 3 to eliminate denominators,
{{{6t+3t+5t+1=15}}}
{{{14t+1=15}}}
{{{14t=15-1}}}
{{{14t=14}}}
{{{t=1}}}
Dominique waited at Cleveland for {{{highlight(1 hour)}}} .