Question 1088557
Let the short leg be n. Then the longer leg would be n+6; and the hypotenuse would be n+12. Then:
n²+(n+6)²=(n+12)²
n²+n²+12n+36=n²+24n+144
n²-12n-108=0
(n-18)(n+6)=0
n=18 or -6
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