Question 1088508
Let a=smallest of the 3 integers
a + (a+1) + (a+2) = 81
3a + 3 = 81 
3a = 78  —>   a = 26
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Ans:  The three numbers are 26, 27, and 28
Check:  26+27+28 = 81 (ok)
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Another method.  Since the integers are consecutive,  3 times the average (which will be a+1) of the three numbers will be 81: 
     3(a+1) = 81
        a+ 1 = 27
          a = 26  —>  the same answer 26, 27, 28 is obtained.

[ This method works for other evenly spaced integer problems, this particular problem has them spaced one apart.  Just be sure to check your work by checking your answer. ]
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