Question 1088256

{{{f(x)=sqrt((x+1)/(x-1))}}}.....to find out what the domain and range are


{ {{{x}}} element {{{R}}} : {{{x<=-1}}} or {{{x>1}}} }

range:
{ {{{f(x) element {{{R}}} : {{{0<=f(x)<1}}} or {{{f(x)>1}}} }



{{{g(x)=sqrt((x+1))/sqrt((x-1))}}}

domain:

{ {{{x}}} element {{{R}}} : {{{x>1}}} }

range:

{ {{{g(x)}}} element {{{R}}} : {{{g(x)>1}}} }

so, {{{f(x)}}} and {{{g(x)}}} are not same because they have different domain and range