Question 1088424

{{{h(x)=sqrt(x+5)/sqrt(x^2-9)}}}  to find domain exclude values of {{{x}}} that make denominator equal to zero 

{{{x^2-9=0}}}=>{{{x^2=9}}} =>{{{x=3}}} or {{{x=-3}}}

numerator: {{{x+5=0}}}=>{{{x=-5}}}

since we do not want sqrt of negative number, your domain will be:

{ {{{x}}} element {{{R}}} : {{{-5<=x<-3}}} or {{{x>3}}} }