Question 1088371
{{{-2(x+1)^2-5=mx-7}}}
{{{-2(x^2+2x+1)-5=mx-7}}}
{{{-2x^2-4x-2-5-mx+7=0}}}
{{{-2x^2-(4+m)x=0}}}
{{{-x(2x+(4+m))=0}}}
{{{x(2x+(4+m))=0}}}
Two zeros:
{{{x=0}}}
and
{{{2x=-(4+m)}}}
{{{x=(4+m)/2}}}
{{{x=-(2+m/2)}}}
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Example: When {{{m=2}}}, the zeroes are {{{x=0}}}
and {{{x=-(2+2/2)=-(2+1)=-3}}}
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*[illustration dfv1.JPG].