Question 1088367
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What is written in the post is not a quadratic equation.



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<U>Comment from student</U>: Ah.. sorry I didn't simplify it enough, but now I got it, the equation is x^2-6x-1=0
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<U>My response</U>:


<pre>
{{{x^2 - 6x - 1}}} = 0  ====>  Use quadratic formula  ====>

{{{x[1,2]}}} = {{{(6 +- sqrt(6^2 + 4))/2}}} = {{{(6 +- sqrt(40))/2}}} = {{{3 +- sqrt(10)}}}.


{{{x[1]}}} = {{{3 + sqrt(10)}}};   {{{x[2]}}} = {{{3 - sqrt(10)}}}.
</pre>

Solved.



On using quadratic formula to solve quadratic equations see the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/Introduction-Into-Quadratics.lesson>Introduction into Quadratic Equations</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/proof-of-quadratic-by-completing-the-square.lesson>PROOF of quadratic formula by completing the square</A>

in this site.


Also, you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lessons are the part of this textbook under the topic "<U>Quadratic equations</U>".